Diregularity of digraphs of out-degree three and order two less than Moore bound
dc.contributor.author | Slamin | |
dc.contributor.author | Miller, M. | |
dc.contributor.author | Baskoro, E. T. | |
dc.date.accessioned | 2013-08-22T04:20:34Z | |
dc.date.available | 2013-08-22T04:20:34Z | |
dc.date.issued | 2001 | |
dc.identifier.uri | http://repository.unej.ac.id/handle/123456789/815 | |
dc.description.abstract | It is easy to show that any digraph with out-degree at most $d \ge 2$, diameter $k \ge 2$ and order $n=d+d^2+\dots + d^k - 1$, that is, two less than Moore bound must have all vertices of out-degree $d$. In other words, the out-degree of the digraph is constant $(=d)$. However, establishing the diregularity or otherwise of the in-degree of such a digraph is not easy. It was proved that every digraph of out-degree at most two, diameter $k \ge 3$ and order two less than the Moore bound is diregular \cite{SM00}. In this paper, we consider the diregularity of digraphs of out-degree at most three, diameter $k \ge 3$ and order two less than the Moore bound. | en_US |
dc.language.iso | en_US | en_US |
dc.publisher | Proceeding of 12th Australasian Workshop on Combinatorial Algorithms | en_US |
dc.subject | diregularity | en_US |
dc.subject | Moore bound | en_US |
dc.title | Diregularity of digraphs of out-degree three and order two less than Moore bound | en_US |
dc.type | Article | en_US |
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